x^2=0.25-0.5x

Solution for x^2=0.25-0.5x equation:

x^2=0.25-0.5x

We move all terms to the left:

x^2-(0.25-0.5x)=0

We add all the numbers together, and all the variables

x^2-(-0.5x+0.25)=0

We get rid of parentheses

x^2+0.5x-0.25=0

a = 1; b = 0.5; c = -0.25;
Δ = b2-4ac
Δ = 0.52-4·1·(-0.25)
Δ = 1.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{1.25}}{2*1}=\frac{-0.5-\sqrt{1.25}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{1.25}}{2*1}=\frac{-0.5+\sqrt{1.25}}{2}
$